Which of the following is paramagnetic?
[CoBɣ]2-
Mo(Co)6
[Pt(en)Cl2]
[Co(NH3)6]3+
To determine which of the given complexes is paramagnetic, we need to examine the electronic configuration of the metal centers and the nature of the ligands. Paramagnetism arises from unpaired electrons in an atom, ion, or molecule.
Let's analyze each option:
[CoBɣ]2-: Assuming the ligand "Bγ" doesn't affect the oxidation state, cobalt is typically Co(II) here, which has an electronic configuration of 3d7. This means it has unpaired electrons, indicating paramagnetism.
Mo(CO)6: The Mo atom in Mo(CO)6 is in the zero oxidation state (Mo0), and carbonyl (CO) is a strong field ligand leading to pairing of electrons. Thus, it is diamagnetic.
[Pt(en)Cl2]: Platinum(II) typically has a low-spin d8 configuration with all electrons paired. Therefore, it is diamagnetic.
[Co(NH3)6]3+: The cobalt ion here is Co(III) with a d6 configuration in a low-spin state, which results in paired electrons, making it diamagnetic.
In conclusion, [CoBɣ]2- is paramagnetic due to the presence of unpaired electrons in the cobalt ion.
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