Question:
Which of the following is NOT obtained when a mixture of chloroethane and 1-chloropropane is treated with sodium metal in dry ether?
Which of the following is NOT obtained when a mixture of chloroethane and 1-chloropropane is treated with sodium metal in dry ether?
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In Wurtz reaction with two different alkyl halides, expect symmetrical and unsymmetrical higher alkanes, not smaller alkanes like propane here.
Updated On: May 14, 2026
- Propane
- Butane
- Pentane
- Hexane
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The Correct Option is A
Solution and Explanation
Concept:
This is Wurtz reaction. When two different alkyl halides are used, different coupling products are formed by combining their alkyl groups. ip
Step 1: Write the alkyl groups present.
Chloroethane gives: \[ \text{C}_2\text{H}_5 \] 1-Chloropropane gives: \[ \text{C}_3\text{H}_7 \] ip
Step 2: Find all possible coupling products.
Possible combinations are:
• \(\text{C}_2\text{H}_5-\text{C}_2\text{H}_5\) \(\rightarrow\) Butane
• \(\text{C}_3\text{H}_7-\text{C}_3\text{H}_7\) \(\rightarrow\) Hexane
• \(\text{C}_2\text{H}_5-\text{C}_3\text{H}_7\) \(\rightarrow\) Pentane e} ip
Step 3: Identify the compound not formed.
Propane cannot be formed from these coupling combinations. ip Hence, the correct answer is:
\[ \boxed{(A)\ \text{Propane}} \]
This is Wurtz reaction. When two different alkyl halides are used, different coupling products are formed by combining their alkyl groups. ip
Step 1: Write the alkyl groups present.
Chloroethane gives: \[ \text{C}_2\text{H}_5 \] 1-Chloropropane gives: \[ \text{C}_3\text{H}_7 \] ip
Step 2: Find all possible coupling products.
Possible combinations are:
• \(\text{C}_2\text{H}_5-\text{C}_2\text{H}_5\) \(\rightarrow\) Butane
• \(\text{C}_3\text{H}_7-\text{C}_3\text{H}_7\) \(\rightarrow\) Hexane
• \(\text{C}_2\text{H}_5-\text{C}_3\text{H}_7\) \(\rightarrow\) Pentane e} ip
Step 3: Identify the compound not formed.
Propane cannot be formed from these coupling combinations. ip Hence, the correct answer is:
\[ \boxed{(A)\ \text{Propane}} \]
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