Question:
Which of the following is not correct for \(D_2O\) ?
Which of the following is not correct for \(D_2O\) ?
Show Hint
Heavier isotope → stronger bonding → higher B.P., higher viscosity, slower reactions, but lower solubility.
Updated On: Apr 15, 2026
- B.P. is higher than \(H_2O\)
- \(D_2O\) reacts more slowly than \(H_2O\)
- Viscosity is higher than \(H_2O\) at \(25^\circ C\)
- Solubility of NaCl in it is more than \(H_2O\)
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Concept: Properties of Heavy Water (\(D_2O\))
Heavy water contains deuterium (\(^2H\)) instead of hydrogen (\(^1H\)), which makes it heavier and leads to stronger intermolecular interactions.
Step 1: Boiling point \[ \text{B.P. of } D_2O>H_2O \] Due to stronger hydrogen bonding → Correct
Step 2: Reaction rate \[ D_2O \text{ reacts more slowly} \] Heavier isotope → slower bond breaking (kinetic isotope effect) → Correct
Step 3: Viscosity \[ \text{Viscosity of } D_2O>H_2O \] Stronger intermolecular attraction → Correct
Step 4: Solubility of salts \[ \text{Solubility in } D_2O<H_2O \] Stronger hydrogen bonding reduces ion solvation → Lower solubility So statement: \[ \text{“Solubility is more”} \quad \Rightarrow Incorrect \] Final Answer: D
Step 1: Boiling point \[ \text{B.P. of } D_2O>H_2O \] Due to stronger hydrogen bonding → Correct
Step 2: Reaction rate \[ D_2O \text{ reacts more slowly} \] Heavier isotope → slower bond breaking (kinetic isotope effect) → Correct
Step 3: Viscosity \[ \text{Viscosity of } D_2O>H_2O \] Stronger intermolecular attraction → Correct
Step 4: Solubility of salts \[ \text{Solubility in } D_2O<H_2O \] Stronger hydrogen bonding reduces ion solvation → Lower solubility So statement: \[ \text{“Solubility is more”} \quad \Rightarrow Incorrect \] Final Answer: D
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