Question

Which of the following is correct decreasing order of bond length regarding $N_{2}$, $O_{2}$ and $Cl_{2}$?

• A. $Cl_{2} > O_{2} > N_{2}$
• B. $Cl_{2} > N_{2} > O_{2}$
• C. $O_{2} > N_{2} > Cl_{2}$
• D. $N_{2} > O_{2} > Cl_{2}$

Hint:

Single Bond > Double Bond > Triple Bond (Length).

Answer 1

The Correct Option is A

Step 1: Concept
Bond length is inversely proportional to bond order (number of bonds between atoms).

Step 2: Analysis
- $N_{2}$: Triple bond (Bond Order = 3). - $O_{2}$: Double bond (Bond Order = 2). - $Cl_{2}$: Single bond (Bond Order = 1).

Step 3: Comparison
Higher bond order leads to shorter bond length. Also, $Cl$ has a larger atomic radius than $N$ or $O$.

Step 4: Conclusion
Decreasing order of bond length: $Cl_{2} (Single) > O_{2} (Double) > N_{2} (Triple)$. Final Answer: (A)