Question:
Which of the following is confirmed by the reaction of glucose with hydroxylamine?
Which of the following is confirmed by the reaction of glucose with hydroxylamine?
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Hydroxylamine tests for a carbonyl group.
Updated On: Oct 1, 2026
- Straight chain of six carbon atoms
- Carbonyl group
- Primary alcoholic group
- Secondary alcoholic group
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Hydroxylamine (\(NH_2OH\)) reacts with carbonyl compounds, aldehydes and ketones, to give oximes.
Step 2: Apply to glucose:
Glucose reacts with hydroxylamine to form glucose oxime. This shows that there is a carbonyl group, here an aldehyde group at C1, in glucose.
Step 3: Check the options:
Straight six-carbon chain is shown by reduction with HI. A primary alcohol and secondary alcohols are shown by acetylation or reaction with acid anhydrides. So (B) is correct.
Final Answer:
Reaction with hydroxylamine proves a carbonyl group. \[ \boxed{B:\ \text{Carbonyl group}} \]
Hydroxylamine (\(NH_2OH\)) reacts with carbonyl compounds, aldehydes and ketones, to give oximes.
Step 2: Apply to glucose:
Glucose reacts with hydroxylamine to form glucose oxime. This shows that there is a carbonyl group, here an aldehyde group at C1, in glucose.
Step 3: Check the options:
Straight six-carbon chain is shown by reduction with HI. A primary alcohol and secondary alcohols are shown by acetylation or reaction with acid anhydrides. So (B) is correct.
Final Answer:
Reaction with hydroxylamine proves a carbonyl group. \[ \boxed{B:\ \text{Carbonyl group}} \]
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