Step 1: First-Order Predicate Logic (FOPL) uses predicates over objects, variables, and quantifiers like \( \forall \) and \( \exists \).
Step 2: Option (A), \( P \rightarrow Q \), uses only propositional symbols, so it is propositional logic, not first-order.
Step 3: Option (B), \( P + Q = R \), is an arithmetic equation, not a logic formula. Option (D) quantifies over a predicate symbol P, which is not allowed in first-order logic (that would be higher-order).
Step 4: Option (C), \( \forall x\,(\text{Student}(x) \rightarrow \text{Studies}(x)) \), quantifies over a variable x and applies predicates to it. It reads 'every student studies', a well-formed FOPL sentence.
Correct option: (C).