Question:

Which of the following is a secondary benzylic alcohol?

Show Hint

Logic Tip: A simple counting rule for alcohols: If the $-OH$ bearing carbon has $CH_2$, it's primary. If it has $CH$, it's secondary. If it has just $C$ (no hydrogens), it's tertiary. "Benzylic" just means the nearest neighbor is a benzene ring.
Updated On: Apr 28, 2026
  • $\text{C}_6\text{H}_5-\text{CH}_2-\text{OH}$
  • $\text{C}_6\text{H}_5-\text{CH}(\text{OH})-\text{CH}_3$
  • $\text{C}_6\text{H}_5-\text{C}(\text{CH}_3)_2-\text{OH}$
  • $\text{C}_6\text{H}_5-\text{OH}$
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept:
Alcohols are classified based on the hybridization and environment of the carbon atom to which the hydroxyl ($-OH$) group is attached.
  • Benzylic alcohol: The $-OH$ group is attached to an $sp^3$-hybridized carbon atom that is directly attached to an aromatic ring (benzene ring).
  • Primary/Secondary/Tertiary: This classification depends on how many other carbon atoms are directly attached to the carbon holding the $-OH$ group. A secondary ($2^\circ$) alcohol has exactly two carbon atoms attached to the hydroxyl-bearing carbon.

Step 1: Analyze the structure of a secondary benzylic alcohol.
For a compound to be a secondary benzylic alcohol, the central carbon must be attached to: 1. The $-OH$ group. 2. A benzene ring (phenyl group, $C_6H_5-$). 3. One other alkyl group (e.g., a methyl group, $-CH_3$). 4. One hydrogen atom. This yields the general formula: $Ar-CH(OH)-R$.
Step 2: Evaluate the given options.
Let's classify each of the chemical structures provided:
  • (A) $C_6H_5-CH_2-OH$ (Benzyl alcohol): The carbon with the $-OH$ is attached only to the benzene ring. This is a primary ($1^\circ$) benzylic alcohol.
  • (B) $C_6H_5-CH(OH)-CH_3$ (1-Phenylethanol): The carbon with the $-OH$ is attached to the benzene ring and one methyl group. This is a secondary ($2^\circ$) benzylic alcohol.
  • (C) $C_6H_5-C(CH_3)_2-OH$ (2-Phenylpropan-2-ol): The carbon with the $-OH$ is attached to the benzene ring and two methyl groups. This is a tertiary ($3^\circ$) benzylic alcohol.
  • (D) $C_6H_5-OH$ (Phenol): The $-OH$ group is attached directly to the $sp^2$-hybridized carbon of the aromatic ring. This is a phenol, not a benzylic alcohol.
Option (B) perfectly matches the criteria for a secondary benzylic alcohol.
Was this answer helpful?
0
0