Question:
Which of the following has maximum number of electrons in \(t_{2g}\) orbitals?
Which of the following has maximum number of electrons in \(t_{2g}\) orbitals?
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Strong field ligands like CN$^-$ and NH$_3$ cause pairing of electrons, increasing the number of electrons in \(t_{2g}\) orbitals.
Updated On: Jul 29, 2026
- \([Fe(CN)_6]^{3-}\)
- \([FeCl_6]^{3-}\)
- \([CoCl_6]^{3-}\)
- \([Co(NH_3)_6]^{3+}\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Concept:
In octahedral complexes:
\[
d \text{-orbitals split into } t_{2g} \text{ and } e_g
\]
To find maximum electrons in \(t_{2g}\), first calculate oxidation state and electronic configuration.
Step 1: Check Option (A) \[ [Fe(CN)_6]^{3-} \] Oxidation state of Fe: \[ x+6(-1)=-3 \] \[ x=+3 \] Fe: \[ 3d^5 \] CN- is strong field ligand. Low spin: \[ t_{2g}^{5}e_g^0 \] Number of \(t_{2g}\) electrons: \[ =5 \]
Step 2: Check Option (B) \[ [FeCl_6]^{3-} \] Fe: \[ 3d^5 \] Cl- is weak field ligand. High spin: \[ t_{2g}^{3}e_g^2 \] Number of \(t_{2g}\) electrons: \[ =3 \]
Step 3: Check Option (C) \[ [CoCl_6]^{3-} \] Oxidation state: \[ x+6(-1)=-3 \] \[ x=+3 \] Co: \[ 3d^6 \] Weak field ligand. High spin: \[ t_{2g}^{4}e_g^2 \] Number of \(t_{2g}\) electrons: \[ =4 \]
Step 4: Check Option (D) \[ [Co(NH_3)_6]^{3+} \] Oxidation state: \[ x=+3 \] Co: \[ 3d^6 \] NH\(_3\) is strong field ligand. Low spin: \[ t_{2g}^{6}e_g^0 \] Number of \(t_{2g}\) electrons: \[ =6 \] Maximum \(t_{2g}\) electrons: \[ =6 \] Hence, \[ \boxed{[Co(NH_3)_6]^{3+}} \] Therefore, the correct answer is: \[ \boxed{(D)} \]
Step 1: Check Option (A) \[ [Fe(CN)_6]^{3-} \] Oxidation state of Fe: \[ x+6(-1)=-3 \] \[ x=+3 \] Fe: \[ 3d^5 \] CN- is strong field ligand. Low spin: \[ t_{2g}^{5}e_g^0 \] Number of \(t_{2g}\) electrons: \[ =5 \]
Step 2: Check Option (B) \[ [FeCl_6]^{3-} \] Fe: \[ 3d^5 \] Cl- is weak field ligand. High spin: \[ t_{2g}^{3}e_g^2 \] Number of \(t_{2g}\) electrons: \[ =3 \]
Step 3: Check Option (C) \[ [CoCl_6]^{3-} \] Oxidation state: \[ x+6(-1)=-3 \] \[ x=+3 \] Co: \[ 3d^6 \] Weak field ligand. High spin: \[ t_{2g}^{4}e_g^2 \] Number of \(t_{2g}\) electrons: \[ =4 \]
Step 4: Check Option (D) \[ [Co(NH_3)_6]^{3+} \] Oxidation state: \[ x=+3 \] Co: \[ 3d^6 \] NH\(_3\) is strong field ligand. Low spin: \[ t_{2g}^{6}e_g^0 \] Number of \(t_{2g}\) electrons: \[ =6 \] Maximum \(t_{2g}\) electrons: \[ =6 \] Hence, \[ \boxed{[Co(NH_3)_6]^{3+}} \] Therefore, the correct answer is: \[ \boxed{(D)} \]
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