Step 1: Understanding the structure.
XeF\(_4\) has a square planar structure due to the presence of two lone pairs of electrons on the central xenon atom. This gives a total of four bonds, forming a square planar geometry.
Step 2: Analyzing the options.
- (A) XeF\(_4\) has a square planar structure with two lone pairs on the xenon atom.
- (B) NiF\(_4\) has a tetrahedral structure, not planar, with no lone pairs on the central atom.
- (C) SF\(_4\) has a seesaw structure with one lone pair.
- (D) SF\(_6\) has an octahedral structure with no lone pairs.
Step 3: Conclusion.
The correct answer is (A), as XeF\(_4\) has a square planar structure with two lone pairs.