Question:

Which of the following equations shows the relationship between heat of reaction at constant pressure and heat of reaction at constant volume if the temperature is not constant?

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Always remember: for gaseous reactions, \( \Delta H = \Delta U + \Delta nRT \).
Updated On: Feb 11, 2026
  • \( \Delta H - \Delta n = \Delta U RT \)
  • \( \Delta H - \Delta U = \Delta n RT \)
  • \( \Delta H = \Delta n RT \)
  • \( \Delta H = \Delta U - RT \)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding thermodynamic terms.
At constant pressure, the heat of reaction is represented by enthalpy change \( \Delta H \), while at constant volume, it is represented by internal energy change \( \Delta U \). The difference between these two arises due to work done by gases during expansion or contraction.

Step 2: Relation between \( \Delta H \) and \( \Delta U \).
For reactions involving gases, the relationship between enthalpy change and internal energy change is given by:
\[ \Delta H = \Delta U + \Delta n RT \] where \( \Delta n \) is the change in number of moles of gaseous species.

Step 3: Rearranging the equation.
Rearranging the above expression, we get:
\[ \Delta H - \Delta U = \Delta n RT \]

Step 4: Conclusion.
Thus, the correct relationship between heat of reaction at constant pressure and constant volume is option (B).
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