Question:
Which of the following electrolytes is least effective in coagulating ferric hydroxide solution?
Which of the following electrolytes is least effective in coagulating ferric hydroxide solution?
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Which of the following electrolytes is least effective in coagulating ferric hydroxide solution?
Updated On: Apr 15, 2026
- KBr
- $K_{2}SO_{4}$
- $K_{2}CrO_{4}$
- $K_{4}[Fe(CN)_{6}]$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Ferric hydroxide ($Fe(OH)_{3}$) is a positively charged sol. According to the Hardy-Schulze rule, it is coagulated by negative ions (anions).
Step 2: Analysis
Coagulating power increases with the increase in the valency of the coagulating ion.
Step 3: Comparison
- $Br^{-}$ (from KBr) has a charge of -1.
- $SO_{4}^{2-}$ has a charge of -2.
- $CrO_{4}^{2-}$ has a charge of -2.
- $[Fe(CN)_{6}]^{4-}$ has a charge of -4.
Step 4: Conclusion
Since $Br^{-}$ has the smallest charge, it is the least effective.
Final Answer: (A)
Ferric hydroxide ($Fe(OH)_{3}$) is a positively charged sol. According to the Hardy-Schulze rule, it is coagulated by negative ions (anions).
Step 2: Analysis
Coagulating power increases with the increase in the valency of the coagulating ion.
Step 3: Comparison
- $Br^{-}$ (from KBr) has a charge of -1.
- $SO_{4}^{2-}$ has a charge of -2.
- $CrO_{4}^{2-}$ has a charge of -2.
- $[Fe(CN)_{6}]^{4-}$ has a charge of -4.
Step 4: Conclusion
Since $Br^{-}$ has the smallest charge, it is the least effective.
Final Answer: (A)
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