Step 1: Understanding the Question:
The question asks to identify the compound that reduces ammoniacal silver nitrate solution (Tollens' reagent) to yield a solid shiny precipitate of elemental silver (the classic silver mirror test).
Step 2: Detailed Explanation:
Ammoniacal silver nitrate solution acts as Tollens' reagent, which is a mild oxidizing agent. This reagent reacts selectively with aldehydes.
Aldehydes are easily oxidized into their corresponding carboxylate anions, and in turn, they reduce the silver complex ions ($\text{[Ag(NH}_3)_2]^+$) down to metallic silver metal atoms that coat the inner walls of the vessel:
$$ \text{R-CHO} + 2[\text{Ag(NH}_3)_2]^+ + 3\text{OH}^- \longrightarrow \text{R-COO}^- + 2\text{Ag}_{(s)}\downarrow + 4\text{NH}_3 + 2\text{H}_2\text{O} $$
Among the given choices:
• Ethanal ($\text{CH}_3\text{CHO}$) is an aldehyde, so it gives a positive Tollens' test.
• Ethanoic acid (carboxylic acid), Ethanol (alcohol), and Ethoxy ethane (ether) are resistant to oxidation by Tollens' reagent and will not produce a silver precipitate.
Step 3: Final Answer:
The compound that forms a silver precipitate upon reacting with ammoniacal silver nitrate is Ethanal, which corresponds to option (A).