Question:
Which of the following compounds is obtained when Bromoethane is reacted with silver acetate?
Which of the following compounds is obtained when Bromoethane is reacted with silver acetate?
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Silver acetate is a source of the acetate ion, which replaces bromine in a substitution reaction and gives an ester.
Updated On: Oct 1, 2026
- propanal
- acetic acid
- ethyl acetate
- methyl acetate
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Bromoethane is a primary alkyl halide. Silver salts of carboxylic acids react with alkyl halides in a nucleophilic substitution. The halogen leaves as silver bromide, which is insoluble.
Step 2: Key Formula or Approach:
\[ \text{R-X} + \text{R'COOAg} \to \text{R'COOR} + \text{AgX} \downarrow \]
Step 3: Detailed Explanation:
Here R = ethyl and R' = methyl.
\[ \text{C}_2\text{H}_5\text{Br} + \text{CH}_3\text{COOAg} \to \text{CH}_3\text{COOC}_2\text{H}_5 + \text{AgBr} \downarrow \]
The product is an ester made of the acetyl part (from acetate) and the ethyl part (from bromoethane). Its name is ethyl acetate.
Step 4: Why the other options are wrong.
Propanal is an aldehyde and acetic acid is a free acid, and neither forms by simple substitution. Methyl acetate would need a methyl halide, but we started with an ethyl halide.
Final Answer:
The product is ethyl acetate, option (C). \[ \boxed{\text{CH}_3\text{COOC}_2\text{H}_5} \]
Bromoethane is a primary alkyl halide. Silver salts of carboxylic acids react with alkyl halides in a nucleophilic substitution. The halogen leaves as silver bromide, which is insoluble.
Step 2: Key Formula or Approach:
\[ \text{R-X} + \text{R'COOAg} \to \text{R'COOR} + \text{AgX} \downarrow \]
Step 3: Detailed Explanation:
Here R = ethyl and R' = methyl.
\[ \text{C}_2\text{H}_5\text{Br} + \text{CH}_3\text{COOAg} \to \text{CH}_3\text{COOC}_2\text{H}_5 + \text{AgBr} \downarrow \]
The product is an ester made of the acetyl part (from acetate) and the ethyl part (from bromoethane). Its name is ethyl acetate.
Step 4: Why the other options are wrong.
Propanal is an aldehyde and acetic acid is a free acid, and neither forms by simple substitution. Methyl acetate would need a methyl halide, but we started with an ethyl halide.
Final Answer:
The product is ethyl acetate, option (C). \[ \boxed{\text{CH}_3\text{COOC}_2\text{H}_5} \]
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