Question:
Which of the following compounds is obtained when \( \mathrm{C_2H_5NH_2} \) is treated with excess \( (\mathrm{CH_3CO})_2\mathrm{O} \) in presence of pyridine?
Which of the following compounds is obtained when \( \mathrm{C_2H_5NH_2} \) is treated with excess \( (\mathrm{CH_3CO})_2\mathrm{O} \) in presence of pyridine?
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Excess acylating agent leads to complete acylation of amines.
Updated On: Feb 11, 2026
- \( \mathrm{C_2H_5N(COCH_3)_2} \)
- \( (\mathrm{C_2H_5})_2\mathrm{NH} \)
- \( \mathrm{C_2H_5COOH} \)
- \( \mathrm{C_2H_5NHCOCH_3} \)
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The Correct Option is A
Solution and Explanation
Step 1: Nature of ethylamine.
Ethylamine is a primary amine and contains an active hydrogen atom attached to nitrogen.
Step 2: Reaction with excess acetic anhydride.
When treated with excess acetic anhydride in presence of pyridine, both hydrogen atoms of the amine group are replaced by acetyl groups.
Step 3: Formation of diacetyl derivative.
This leads to the formation of N,N-diacetyl ethylamine.
Step 4: Conclusion.
Hence, the product formed is \( \mathrm{C_2H_5N(COCH_3)_2} \).
Ethylamine is a primary amine and contains an active hydrogen atom attached to nitrogen.
Step 2: Reaction with excess acetic anhydride.
When treated with excess acetic anhydride in presence of pyridine, both hydrogen atoms of the amine group are replaced by acetyl groups.
Step 3: Formation of diacetyl derivative.
This leads to the formation of N,N-diacetyl ethylamine.
Step 4: Conclusion.
Hence, the product formed is \( \mathrm{C_2H_5N(COCH_3)_2} \).
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