Question:
Which of the following compounds gives a positive Hinsberg test and forms a soluble sulphonamide?
Which of the following compounds gives a positive Hinsberg test and forms a soluble sulphonamide?
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Hinsberg test:
\[
1^\circ \text{ amine } \rightarrow \text{Soluble product}
\]
\[
2^\circ \text{ amine } \rightarrow \text{Insoluble product}
\]
\[
3^\circ \text{ amine } \rightarrow \text{No reaction}
\]
Updated On: Jun 3, 2026
- Aniline
- Dimethylamine
- Trimethylamine
- Triphenylamine
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The Correct Option is A
Solution and Explanation
Concept:
Hinsberg reagent is:
\[
\text{Benzenesulphonyl chloride}
\]
It is used to distinguish primary, secondary and tertiary amines.
Step 1: Understand the reaction of primary amines. Primary amines contain one replaceable hydrogen atom attached to nitrogen. They react with Hinsberg reagent to form sulphonamides having acidic hydrogen. These dissolve in alkali due to salt formation.
Step 2: Identify the primary amine. Among the given compounds: \[ \text{Aniline } (\text{C}_6\text{H}_5\text{NH}_2) \] is a primary amine.
Step 3: Conclusion. Hence aniline forms soluble sulphonamide in Hinsberg test. \[ \boxed{\text{Aniline}} \]
- Primary amines form sulphonamides soluble in alkali.
- Secondary amines form insoluble sulphonamides.
- Tertiary amines do not react.
Step 1: Understand the reaction of primary amines. Primary amines contain one replaceable hydrogen atom attached to nitrogen. They react with Hinsberg reagent to form sulphonamides having acidic hydrogen. These dissolve in alkali due to salt formation.
Step 2: Identify the primary amine. Among the given compounds: \[ \text{Aniline } (\text{C}_6\text{H}_5\text{NH}_2) \] is a primary amine.
Step 3: Conclusion. Hence aniline forms soluble sulphonamide in Hinsberg test. \[ \boxed{\text{Aniline}} \]
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