Step 1: Understanding the Concept:
Iodoform forms from compounds containing \(\text{CH}_3\text{CO-}\) or \(\text{CH}_3\text{CH(OH)-}\). Ethanol is the only primary alcohol that does.
Step 2: Check each:
A: Ethyl methyl ketone, \(\text{CH}_3\text{COCH}_2\text{CH}_3\), has \(\text{CH}_3\text{CO-}\). It gives iodoform.
B: Isopropyl alcohol, \(\text{CH}_3\text{CH(OH)CH}_3\), has \(\text{CH}_3\text{CH(OH)-}\). It gives iodoform.
C: 3-Methylbutan-2-one, \(\text{CH}_3\text{COCH(CH}_3)_2\), has \(\text{CH}_3\text{CO-}\). It gives iodoform.
D: Isobutyl alcohol, \((\text{CH}_3)_2\text{CHCH}_2\text{OH}\), is a primary alcohol. It has no \(\text{CH}_3\text{CH(OH)-}\) unit, so it cannot form iodoform.
Final Answer:
Isobutyl alcohol cannot form iodoform, option (D).
\[ \boxed{\text{Isobutyl alcohol}} \]