Question:

Which of the following combination of 7 identical capacitors each of $2\,\mu F$ gives a capacitance of $\frac{10}{11}\,\mu F$?

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Physics Tip: Remember that capacitors behave the opposite of resistors: series connection reduces total capacitance, while parallel connection increases it.
Updated On: Apr 23, 2026
  • 5 in parallel and 2 in series
  • 4 in parallel and 3 in series
  • 3 in parallel and 4 in series
  • 2 in parallel and 5 in series
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The Correct Option is A

Solution and Explanation

Concept: Physics (Electrostatics) - Combinations of Capacitors.

Step 1:
Recall the formulas for capacitor combinations.
• For $n$ identical capacitors connected in series, the equivalent capacitance is $C_{s} = \frac{C}{n}$.
• For $m$ identical capacitors connected in parallel, the equivalent capacitance is $C_{p} = mC$.

Step 2:
Evaluate the specific combination for Option A. For 5 capacitors in parallel, $C_p = 5C = 5(2\mu F) = 10\mu F$. If this combination is then placed in series with 2 more capacitors, the net capacitance $C_{net}$ is found by: $$\frac{1}{C_{net}} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C} = \frac{1}{10} + \frac{1}{2} + \frac{1}{2}$$ $$\frac{1}{C_{net}} = \frac{1}{10} + 1 = \frac{11}{10} \implies C_{net} = \frac{10}{11} \mu F$$ $$ \therefore \text{The correct combination is 5 in parallel and 2 in series.} $$
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