



To determine which of the circuits is reverse-biased, we need to understand what reverse biasing means in the context of a diode within a circuit.
From the analysis, Circuit 4 is the only circuit where the diode is reverse-biased. Hence, the correct answer is:
This solution is based on the fundamental principles of diode operation concerning forward and reverse biasing. In a reverse-biased condition, current does not flow due to the orientation of the voltage across the diode.
In a diode circuit, for the diode to be forward-biased, the P-end should be connected to a higher potential than the N-end. In option (4), the P-end of the diode is connected to the negative terminal of the power supply, while the N-end is connected to the positive terminal. This configuration causes the diode to be reverse-biased, as it is in opposition to the direction required for forward bias.
Thus the correct answer is option 4.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,




What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)