Question:

Which of the following changes in the respective bond order values are caused by removal of an electron from N$_2$ and F$_2$ molecules?

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Removing antibonding electron increases bond order.
Updated On: May 8, 2026
  • decrease by 0.5 in both
  • increase by 0.5 in both
  • increase by 0.5 in the former and decrease by 0.5 in the later
  • decrease by 0.5 in the former and increase by 0.5 in the later
  • no change in both
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The Correct Option is C

Solution and Explanation

Concept: Bond order: \[ BO = \frac{N_b - N_a}{2} \]

Step 1:
N$_2$ configuration. Bond order = 3 Removing electron from bonding orbital: \[ BO = 2.5 \Rightarrow \text{decrease} \]

Step 2:
F$_2$ configuration. Bond order = 1 Removing electron from antibonding orbital: \[ BO = 1.5 \Rightarrow \text{increase} \]

Step 3:
Conclusion. \[ \boxed{\text{Decrease in N$_2$, increase in F$_2$}} \]
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