Which of the following changes alone would cause increase in the value of the equilibrium constant of the reaction?
\(PCl_5(g) \rightarrow PCl_3(g) + Cl_2(g); \Delta H>0\)
Step 1: The reaction \(PCl_5(g) \rightarrow PCl_3(g) + Cl_2(g)\) is endothermic (\(\Delta H>0\)).
Step 2: According to Le Chatelier’s Principle, increasing the temperature of an endothermic reaction shifts the equilibrium to the right, favoring the formation of products.
Step 3: This shift increases the equilibrium constant \(K\), as \(K\) is a measure of product favorability at equilibrium.
Step 4: Therefore, increasing the temperature is the only option listed that will increase the equilibrium constant for this reaction.
For the reaction:
$3Fe_{(s)} + 2O_2{(g)} \rightarrow Fe_3O_4{(s)}$
$\Delta H = -1650\,\text{kJ mol}^{-1}$, $\Delta S = -600\,\text{J K}^{-1} \text{mol}^{-1}$ at $300\,\text{K}$. What is the value of free energy change for the reaction at $300\,\text{K}$?
Kepler's second law (law of areas) of planetary motion leads to law of conservation of