Question:
Which of the following bond has highest mean bond enthalpy?
Which of the following bond has highest mean bond enthalpy?
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Higher bond order $\Rightarrow$ stronger bond $\Rightarrow$ higher bond enthalpy
Updated On: Apr 30, 2026
- $\mathrm{N{=}N}$
- $\mathrm{O{=}O}$
- $\mathrm{N{\equiv}N}$
- $\mathrm{C{\equiv}C}$
- $\mathrm{C{\equiv}O}$
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The Correct Option is
Solution and Explanation
Concept:
Bond enthalpy increases with:
• Bond order (single $<$ double $<$ triple)
• Strength of bond between atoms
Step 1: Compare bond orders.
Triple bonds are stronger than double bonds.
Step 2: Compare given triple bonds.
\[ \mathrm{C{\equiv}O} > \mathrm{N{\equiv}N} > \mathrm{C{\equiv}C} \]
Step 3: Conclusion.
\[ \mathrm{C{\equiv}O} \text{ has the highest bond enthalpy} \]
• Bond order (single $<$ double $<$ triple)
• Strength of bond between atoms
Step 1: Compare bond orders.
Triple bonds are stronger than double bonds.
Step 2: Compare given triple bonds.
\[ \mathrm{C{\equiv}O} > \mathrm{N{\equiv}N} > \mathrm{C{\equiv}C} \]
Step 3: Conclusion.
\[ \mathrm{C{\equiv}O} \text{ has the highest bond enthalpy} \]
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