Question:
Which of the following are the correct statements about D-glucose?
flalign*
I. & It forms oxime with hydroxyl amine &
II. & It forms addition product with NaHSO_3 &
III. & It forms cyanohydrin with HCN &
IV. & It forms saccharic acid with bromine water &
flalign*
Which of the following are the correct statements about D-glucose?
flalign*
I. & It forms oxime with hydroxyl amine &
II. & It forms addition product with NaHSO_3 &
III. & It forms cyanohydrin with HCN &
IV. & It forms saccharic acid with bromine water & flalign*
II. & It forms addition product with NaHSO_3 &
III. & It forms cyanohydrin with HCN &
IV. & It forms saccharic acid with bromine water & flalign*
Show Hint
Bromine water is a mild oxidizing agent that selectively oxidizes the aldehyde group of glucose to gluconic acid.
Updated On: Jun 8, 2026
- II \& III only
- I \& III only
- II \& IV only
- III \& IV only
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Concept:
D-glucose contains an aldehyde group and multiple hydroxyl groups, so it undergoes reactions characteristic of aldehydes.
Step 1: Evaluate statement I.
Glucose reacts with hydroxylamine to form oxime: \[ \text{Glucose} + NH_2OH \rightarrow \text{Oxime} \] Hence, statement I is correct.
Step 2: Evaluate statement II.
Glucose does not form sodium bisulfite addition product easily because the free aldehyde concentration is very low due to cyclic hemiacetal formation. Thus, statement II is incorrect.
Step 3: Evaluate statement III.
Glucose reacts with HCN to form cyanohydrin: \[ RCHO + HCN \rightarrow RCH(OH)CN \] Hence, statement III is correct.
Step 4: Evaluate statement IV.
Bromine water oxidizes glucose into gluconic acid, not saccharic acid. Therefore, statement IV is incorrect. Hence, the correct statements are: \[ \boxed{I\ \&\ III\ only} \]
Step 1: Evaluate statement I.
Glucose reacts with hydroxylamine to form oxime: \[ \text{Glucose} + NH_2OH \rightarrow \text{Oxime} \] Hence, statement I is correct.
Step 2: Evaluate statement II.
Glucose does not form sodium bisulfite addition product easily because the free aldehyde concentration is very low due to cyclic hemiacetal formation. Thus, statement II is incorrect.
Step 3: Evaluate statement III.
Glucose reacts with HCN to form cyanohydrin: \[ RCHO + HCN \rightarrow RCH(OH)CN \] Hence, statement III is correct.
Step 4: Evaluate statement IV.
Bromine water oxidizes glucose into gluconic acid, not saccharic acid. Therefore, statement IV is incorrect. Hence, the correct statements are: \[ \boxed{I\ \&\ III\ only} \]
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