Question:
Which of the following acids does not undergo HVZ reaction?
Which of the following acids does not undergo HVZ reaction?
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HVZ reaction is possible only when \(\alpha\)-hydrogen is present in carboxylic acids.
Updated On: Feb 11, 2026
- Ethanoic acid
- Butanoic acid
- Propanoic acid
- Methanoic acid
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The Correct Option is D
Solution and Explanation
Step 1: Recall HVZ reaction condition.
Hell–Volhard–Zelinsky reaction occurs in carboxylic acids having at least one \(\alpha\)-hydrogen atom.
Step 2: Analyze methanoic acid.
Methanoic acid (\(\mathrm{HCOOH}\)) has no \(\alpha\)-carbon and hence no \(\alpha\)-hydrogen.
Step 3: Analyze other acids.
Ethanoic, propanoic, and butanoic acids contain \(\alpha\)-hydrogen atoms.
Step 4: Conclusion.
Methanoic acid does not undergo HVZ reaction.
Hell–Volhard–Zelinsky reaction occurs in carboxylic acids having at least one \(\alpha\)-hydrogen atom.
Step 2: Analyze methanoic acid.
Methanoic acid (\(\mathrm{HCOOH}\)) has no \(\alpha\)-carbon and hence no \(\alpha\)-hydrogen.
Step 3: Analyze other acids.
Ethanoic, propanoic, and butanoic acids contain \(\alpha\)-hydrogen atoms.
Step 4: Conclusion.
Methanoic acid does not undergo HVZ reaction.
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