Step 1: Concept
Stability of oxidation states in 3d series depends on electronic configuration.
Step 2: Meaning
Vanadium ($Z=23$) has the configuration $[Ar] 3d^3 4s^2$.
Step 3: Analysis
By losing all 5 valence electrons, it achieves a stable noble gas configuration ($[Ar]$), making +5 very stable.
Step 4: Conclusion
Vanadium commonly exists in the stable +5 state (e.g., in $V_2O_5$).
Final Answer: (B)