Step 1: Understanding the Concept:
The oxidation states shown by a transition metal depend on its electronic configuration and stability of the resulting ion.
Step 2: Detailed Explanation:
Zinc (Zn) has the electronic configuration \([Ar] 3d^{10} 4s^2\). It has a completely filled d-orbital. To form a compound, it loses the two 4s electrons to achieve a stable \(3d^{10}\) configuration. It only shows a +2 oxidation state. Therefore, it forms only dihalides (ZnX\(_2\)). Other metals like Ti, V, Mn, Fe can show higher oxidation states.
Step 3: Final Answer:
Zinc forms only dihalides.