Step 1: Compare the species
All four have the attacking atom in period 2: \(C, N, O, F\). The attacking atom holds its lone pair more tightly as electronegativity rises.
Step 2: Rank
Electronegativity order is C < N < O < F. Nucleophilicity runs in the opposite order, so \(CH_3^- > NH_2^- > OH^- > F^-\).
Step 3: Conclusion
\(CH_3^-\) has the highest nucleophilicity because carbon is least electronegative and shares its pair most readily, so it is option (C).
Final Answer:
CH3- is the strongest nucleophile.
\[ \boxed{\text{(C)}\ CH_3^-} \]