Step 1: Understanding the Concept
In the cyclic form, glucose forms a hemiacetal between the C-1 aldehyde group and the C-5 hydroxyl group.
Step 2: Ring formed
The ring contains C-1 to C-5 and one oxygen atom, which gives six atoms in all: five carbons and one oxygen.
Step 3: Name
This ring resembles pyran, so the form is called glucopyranose. C-6 stays outside the ring as \(\text{CH}_{2}\text{OH}\).
Final Answer:
Glucopyranose is a six-membered heterocyclic ring of five carbon atoms and one oxygen atom.
\[ \boxed{\text{(A) }\text{Six membered heterocyclic ring containing five carbon and one oxygen atom}} \]