Question:

Which from following reagents is used in Gatterman-Koch formylation of arene?

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Remember: Gatterman-Koch = "C"arbon "O"nide + HCl. The "C" and "O" in Koch remind you of CO.
Updated On: May 14, 2026
  • $\text{AlH}(\text{i}-\text{Bu})_2$
  • $\text{CO}, \text{HCl} \, (\text{anhyd. AlCl}_3)$
  • $\text{CrO}_2\text{Cl}_2 \, (\text{CS}_2)$
  • $\text{DIBAl}-\text{H}$
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The Correct Option is B

Solution and Explanation


Step 1: Concept

The Gatterman-Koch reaction is a variation of the Friedel-Crafts acylation used to introduce a formyl group (—CHO) into an aromatic ring.

Step 2: Meaning

Formylation refers to the attachment of a formyl group to a substrate.

Step 3: Analysis

In this reaction, benzene or its derivatives are treated with carbon monoxide (CO) and hydrogen chloride (HCl) in the presence of a Lewis acid catalyst like anhydrous $\text{AlCl}_3$ or $\text{CuCl}$ to produce benzaldehyde.

Step 4: Conclusion

Reagent (B) matches the specific requirements for the Gatterman-Koch formylation. Final Answer: (B)
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