Question:
Which from following is the slope of the graph of rate versus concentration of the reactant for first order reaction?
Which from following is the slope of the graph of rate versus concentration of the reactant for first order reaction?
Show Hint
Logic Tip: Do not confuse this with the graph of $\log[\text{Reactant}]$ versus Time ($t$), which yields a slope of $\frac{-k}{2.303}$. Pay close attention to what is plotted on the axes! "Rate vs Concentration" is always a simple linear relationship for first-order kinetics.
Updated On: Apr 28, 2026
- -k
- k
- $\frac{k}{2.303}$
- $\frac{-k}{2.303}$
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Concept:
For a first-order chemical reaction, the rate of the reaction is directly proportional to the first power of the concentration of the reactant. The rate law equation is expressed as: $$\text{Rate} = k[\text{Reactant}]^1$$ where $k$ is the rate constant.
Step 1: Compare the rate law to the equation of a straight line.
We are looking for the graph of Rate (on the y-axis) versus Concentration (on the x-axis). Let $y = \text{Rate}$ and $x = [\text{Reactant}]$. The rate law becomes: $$y = k \cdot x$$ This equation is in the form of a straight line passing through the origin: $$y = mx + c$$ where the y-intercept $c = 0$, and the slope of the line is $m$.
Step 2: Identify the slope.
Comparing $y = kx$ with $y = mx$, we can clearly see that the slope $m$ is equal to the rate constant $k$. $$\text{Slope} = k$$
For a first-order chemical reaction, the rate of the reaction is directly proportional to the first power of the concentration of the reactant. The rate law equation is expressed as: $$\text{Rate} = k[\text{Reactant}]^1$$ where $k$ is the rate constant.
Step 1: Compare the rate law to the equation of a straight line.
We are looking for the graph of Rate (on the y-axis) versus Concentration (on the x-axis). Let $y = \text{Rate}$ and $x = [\text{Reactant}]$. The rate law becomes: $$y = k \cdot x$$ This equation is in the form of a straight line passing through the origin: $$y = mx + c$$ where the y-intercept $c = 0$, and the slope of the line is $m$.
Step 2: Identify the slope.
Comparing $y = kx$ with $y = mx$, we can clearly see that the slope $m$ is equal to the rate constant $k$. $$\text{Slope} = k$$
Was this answer helpful?
0
0
Top MHT CET Chemistry Questions
- The temperature of $32^{\circ}C$ is equivalent to
- The heat of formation of water is $ 260\, kJ $ . How much $ H_2O $ is decomposed by $ 130\, kJ $ of heat ?
- If a metal crystallises in bcc structure with edge length of unit cell $4.29 \times 10^{-8}\, cm$ the radius of metal atom is
- Which of the following oxides can act both as an oxidising agent as well as reducing agent ?
- "The mass and energy both are conserved in an isolated system", is the statement of
View More Questions
Top MHT CET Collision Theory of Chemical Reactions Questions
- For a first-order reaction, the time required to reduce the concentration of the reactant to half its initial value is:
- Find the rate law for the reaction, $\mathrm{CHCl_3(g) + Cl_2(g) \rightarrow CCl_4(g) + HCl(g)}$ if the order of reaction with respect to $\mathrm{CHCl_3}$ is one and $\frac{1}{2}$ with respect to $\mathrm{Cl_2}$.
- The rate for the reaction $2A + B \rightarrow \text{product}$ is $6 \times 10^{-4}\,\mathrm{mol\,dm^{-3}\,s^{-1}}$. Calculate the rate constant if the reaction is first order in $A$ and zeroth order in $B$. Given $[A] = [B] = 0.3\,\text{M}$
- Calculate the rate constant of the first order reaction if 80% of the reactant decomposes in 60 minutes.
- What is the value of rate constant for first order reaction if slope for the graph of rate versus concentration is $2.5 \times 10^{-3}$?
View More Questions
Top MHT CET Questions
- During r- DNA technology, which one of the following enzymes is used for cleaving DNA molecule ?
- In non uniform circular motion, the ratio of tangential to radial acceleration is (r = radius of circle, $v =$ speed of the particle, $\alpha =$ angular acceleration)
- The temperature of $32^{\circ}C$ is equivalent to
- The line $5x + y - 1 = 0$ coincides with one of the lines given by $5x^2 + xy - kx - 2y + 2 = 0 $ then the value of k is
- The heat of formation of water is $ 260\, kJ $ . How much $ H_2O $ is decomposed by $ 130\, kJ $ of heat ?
View More Questions