Question:
Which from following is the general formula of compound obtained when lanthanoid (Ln) reacts with carbon at elevated temperature?
Which from following is the general formula of compound obtained when lanthanoid (Ln) reacts with carbon at elevated temperature?
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When lanthanides react with carbon, they typically form lanthanide carbides like LaC\(_2\) at elevated temperatures.
Updated On: Jun 30, 2026
- LaC\(_2\)
- LaC\(_3\)
- LaC\(_2\)Cl
- LaCl\(_3\)
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The Correct Option is A
Solution and Explanation
Step 1: Reaction of lanthanoids with carbon.
When lanthanoids (such as Lanthanum, \(Ln\)) react with carbon at elevated temperatures, they form carbide compounds. The general product of this reaction is a lanthanum carbide with the formula LaC\(_2\), where lanthanum is bonded to two carbon atoms.
Step 2: Analyze the options.
- LaC\(_2\): This is the correct compound formed by the reaction of lanthanum with carbon.
- LaC\(_3\): This is incorrect because lanthanum typically forms LaC\(_2\) and not LaC\(_3\).
- LaC\(_2\)Cl: This is incorrect as it involves a chlorine atom, which is not formed in this reaction.
- LaCl\(_3\): This is incorrect because it represents a lanthanum chloride, not a carbide.
Step 3: Final Answer.
Thus, the correct answer is option \((1)\) LaC\(_2\).
When lanthanoids (such as Lanthanum, \(Ln\)) react with carbon at elevated temperatures, they form carbide compounds. The general product of this reaction is a lanthanum carbide with the formula LaC\(_2\), where lanthanum is bonded to two carbon atoms.
Step 2: Analyze the options.
- LaC\(_2\): This is the correct compound formed by the reaction of lanthanum with carbon.
- LaC\(_3\): This is incorrect because lanthanum typically forms LaC\(_2\) and not LaC\(_3\).
- LaC\(_2\)Cl: This is incorrect as it involves a chlorine atom, which is not formed in this reaction.
- LaCl\(_3\): This is incorrect because it represents a lanthanum chloride, not a carbide.
Step 3: Final Answer.
Thus, the correct answer is option \((1)\) LaC\(_2\).
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