Question:

Which from following is the correct relationship between molar conductivity (\(\Lambda\)), conductivity (\(\text{k}\)) and molarity (\(\text{M}\)) of solution for electrolyte?

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Always remember: \(\Lambda = \frac{1000k}{C}\). Rearranging gives all required relations.
Updated On: Apr 26, 2026
  • \(\text{k} = \frac{\Lambda \times \text{C}}{1000}\)
  • \(\Lambda = \frac{100 \times \text{k}}{\text{C}}\)
  • \(\Lambda = \frac{\text{k} \times \text{C}}{1000}\)
  • \(\text{k} = \frac{1000 \times \text{C}}{\Lambda}\)
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The Correct Option is A

Solution and Explanation

Concept:
Molar conductivity \((\Lambda)\) is defined as the conductivity of a solution containing one mole of electrolyte placed between electrodes 1 cm apart. Mathematically: \[ \Lambda = \frac{\text{k} \times 1000}{C} \] where:
  • \(\text{k}\) = conductivity
  • \(C\) = molarity (mol L\(^{-1}\))
Step 1: Start from the standard formula. \[ \Lambda = \frac{1000 \text{k}}{C} \]
Step 2: Rearrange to find conductivity. Multiplying both sides by \(C\) and dividing by 1000: \[ \text{k} = \frac{\Lambda \times C}{1000} \]
Step 3: Match with options. This matches option (A).
Step 4: Conclusion. \[ {\text{k} = \frac{\Lambda \times C}{1000}} \]
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