Question:
Which from following is obtained as major product when methoxybenzene is treated with nitrating mixture?
Which from following is obtained as major product when methoxybenzene is treated with nitrating mixture?
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-OCH$_3$ is an ortho/para director and para is favoured by sterics.
Updated On: Oct 1, 2026
- 2-Nitroanisole
- 4-Nitroanisole
- 4-Nitrophenol
- 2-Nitrophenol
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The Correct Option is B
Solution and Explanation
Step 1: Identify the directing group
The methoxy group donates electrons by resonance, so it activates the ring and directs to ortho and para.
Step 2: Nitration
With HNO\(_3\)/H\(_2\)SO\(_4\) the electrophile is NO\(_2^+\). It attacks the ortho and para positions.
Step 3: Major product
The para product is major because the ortho positions are hindered by the OCH\(_3\) group. So the major product is 4-nitroanisole.
Nitrophenols are wrong because the ether group is not cleaved under these conditions.
Final Answer:
The major product is 4-nitroanisole, option (B). \[ \boxed{\text{(B)}} \]
The methoxy group donates electrons by resonance, so it activates the ring and directs to ortho and para.
Step 2: Nitration
With HNO\(_3\)/H\(_2\)SO\(_4\) the electrophile is NO\(_2^+\). It attacks the ortho and para positions.
Step 3: Major product
The para product is major because the ortho positions are hindered by the OCH\(_3\) group. So the major product is 4-nitroanisole.
Nitrophenols are wrong because the ether group is not cleaved under these conditions.
Final Answer:
The major product is 4-nitroanisole, option (B). \[ \boxed{\text{(B)}} \]
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