Question:
Which from following gases when absorbed by concentrated sulphuric acid forms oleum ?
Which from following gases when absorbed by concentrated sulphuric acid forms oleum ?
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Oleum is fuming sulphuric acid made in the contact process.
Updated On: Nov 12, 2026
- \(\text{SO}_{3}\)
- \(\text{Cl}_{2}\)
- \(\text{N}_{2}\text{O}\)
- \(\text{Br}_{2}\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Oleum (fuming sulphuric acid) is \(\text{H}_2\text{S}_2\text{O}_7\). It is obtained when sulphur trioxide dissolves in concentrated sulphuric acid.
Step 2: Why not water
In the contact process \(\text{SO}_3\) is absorbed in conc. \(\text{H}_2\text{SO}_4\) because absorbing it directly in water gives a dense acid mist.
Step 3: Compare the options
\(\text{Cl}_2\), \(\text{N}_2\text{O}\) and \(\text{Br}_2\) do not form oleum. So the gas is \(\text{SO}_3\).
Final Answer:
The gas that forms oleum is sulphur trioxide. \[ \boxed{\text{(A) }\text{SO}_{3}} \]
Oleum (fuming sulphuric acid) is \(\text{H}_2\text{S}_2\text{O}_7\). It is obtained when sulphur trioxide dissolves in concentrated sulphuric acid.
Step 2: Why not water
In the contact process \(\text{SO}_3\) is absorbed in conc. \(\text{H}_2\text{SO}_4\) because absorbing it directly in water gives a dense acid mist.
Step 3: Compare the options
\(\text{Cl}_2\), \(\text{N}_2\text{O}\) and \(\text{Br}_2\) do not form oleum. So the gas is \(\text{SO}_3\).
Final Answer:
The gas that forms oleum is sulphur trioxide. \[ \boxed{\text{(A) }\text{SO}_{3}} \]
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