Step 1: Formula
$EAN = Z - (\text{Oxidation State}) + 2 \times (\text{Coordination Number})$.
Step 2: Calculation
- (A) $[Co(NH_3)_6]^{3+}$: $27 - 3 + (2 \times 6) = 36$ (Krypton, Obeys)
- (B) $Cr(CO)_6$: $24 - 0 + (2 \times 6) = 36$ (Krypton, Obeys)
- (C) $[Zn(NH_3)_4]^{2+}$: $30 - 2 + (2 \times 4) = 36$ (Krypton, Obeys)
- (D) $[Cu(NH_3)_4]^{2+}$: $29 - 2 + (2 \times 4) = 35$ (Does NOT obey)
Step 3: Conclusion $[Cu(NH_3)_4]^{2+}$ does not reach the noble gas configuration of 36.
Final Answer: (D)