Question:
Which factor most critically determines the attachment efficiency of animal cells on microcarriers?
Which factor most critically determines the attachment efficiency of animal cells on microcarriers?
Show Hint
For optimal cell attachment on microcarriers, ensure the surface charge and coating are conducive to cell adhesion.
Updated On: Jun 18, 2025
- Oxygen concentration
- Surface charge and coating of the microcarrier
- Agitation speed
- pH of the medium
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The attachment efficiency of animal cells to microcarriers is most significantly influenced by the surface charge and coating of the microcarrier. These factors help in cell adhesion and proliferation during culture.
Was this answer helpful?
0
0
Top Questions on Cell Biology
- Write the full form of ATP.
- TBSE Class X Board - 2026
- Biology
- Cell Biology
- What is the primary composition of lipid rafts found in plasma membranes?
- CUET (PG) - 2026
- Life Science
- Cell Biology
- During cellular fractionation, which organelle typically forms part of the pellet when centrifuged at 1000g for 10 minutes?
- CUET (PG) - 2026
- Life Science
- Cell Biology
- Draw a neat, labelled diagram of an animal cell showing the Prophase stage of Mitosis with four chromosomes.
- ICSE Class X board - 2026
- Biology
- Cell Biology
Study the diagram given below and match the structure with its functions:
- ICSE Class X board - 2026
- Biology
- Cell Biology
View More Questions
Questions Asked in AP PGECET exam
- The absolute humidity of air at 101.325 kPa is measured to be 0.02 kg of water per kg of dry air. Then the partial pressure of water vapour in the air is:
- AP PGECET - 2025
- Thermodynamics
- If the vapour pressure at two temperatures of a solid phase in equilibrium with its liquid phase is known, then the latent heat of fusion can be calculated by the:
- AP PGECET - 2025
- Thermodynamics
- 1 mole of Argon gas is heated at constant pressure from 200 K to 600 K.
If \( C_p = 4\ \text{cal} \cdot \text{deg}^{-1} \cdot \text{mol}^{-1} \), then the change in entropy will be:
(Given \( \ln 3 = 1.09 \))
- AP PGECET - 2025
- Thermodynamics
- The minimum amount of work required to operate a refrigerator which removes 1000 Cal heat at $0^\circ$C and rejects at $50^\circ$C will be:
- AP PGECET - 2025
- Thermodynamics
- The entropy of single crystalline Silicon at absolute zero will be:
- AP PGECET - 2025
- Thermodynamics
View More Questions