Question:

Which element from following exhibits anomalous behavior with remaining three members?

Show Hint

The first member of a group differs because of its small size and high electronegativity.
Updated On: Nov 12, 2026
  • \(\text{F}\)
  • \(\text{Cl}\)
  • \(\text{Br}\)
  • \(\text{I}\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
The first element of a p-block group often behaves differently from the rest because of small size, high electronegativity and absence of d orbitals.

Step 2: Apply to halogens
Fluorine is the smallest and most electronegative halogen.
It shows only the oxidation state \(-1\), forms very strong hydrogen bonds in HF and has an unusually weak F-F bond.

Step 3: Compare the options
Chlorine, bromine and iodine show similar trends and variable oxidation states.
So fluorine is anomalous.

Final Answer:
Fluorine is the anomalous halogen. \[ \boxed{\text{(A) }\text{F}} \]
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