Question:

Which compound is expected to be optically active?

Show Hint

Chiral center = Carbon with 4 different substituents.
Updated On: Apr 8, 2026
  • $(CH_{3})_{2}CHCHO$
  • $CH_{3}CH_{2}CH_{2}CHO$
  • $CH_{3}CH_{2}CHBrCHO$
  • $CH_{3}CH_{2}CBr_{2}CHO$
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Concept
Optical activity requires an asymmetric carbon atom.
Step 2: Analysis

$CH_{3}CH_{2}CHBrCHO$ has a C-atom with four different groups.
Step 3: Conclusion

Different groups bonded to the chiral center enable optical activity.
Final Answer: (C)
Was this answer helpful?
0
0