Question:
How many enols (including stereo isomers) exist for 3-hexanone?
How many enols (including stereo isomers) exist for 3-hexanone?
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Total enols = number of $\alpha$-positions $\times$ geometrical isomers.
Updated On: Apr 23, 2026
- Two
- Three
- Four
- Six
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
Enols are formed by $\alpha$-hydrogen shift. Each $\alpha$-carbon can form an enol. Also, enols can show geometrical (E/Z) isomerism due to C=C bond.
Step 1: Write structure of 3-hexanone
CH$_3$–CH$_2$–CO–CH$_2$–CH$_2$–CH$_3$
Step 2: Identify $\alpha$-carbons
Two $\alpha$-positions exist (on both sides of carbonyl).
Step 3: Number of enols
Each $\alpha$-position gives one enol → total = 2
Step 4: Stereoisomerism
Each enol has C=C bond → shows E and Z isomerism. \[ \text{Total enols} = 2 \times 2 = 4 \] Conclusion:
Total enols = 4
Step 1: Write structure of 3-hexanone
CH$_3$–CH$_2$–CO–CH$_2$–CH$_2$–CH$_3$
Step 2: Identify $\alpha$-carbons
Two $\alpha$-positions exist (on both sides of carbonyl).
Step 3: Number of enols
Each $\alpha$-position gives one enol → total = 2
Step 4: Stereoisomerism
Each enol has C=C bond → shows E and Z isomerism. \[ \text{Total enols} = 2 \times 2 = 4 \] Conclusion:
Total enols = 4
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