Question:

Which clustering algorithm can detect clusters of arbitrary shape and handle noise effectively ?

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If you see "Arbitrary Shape" and "Noise" together in a clustering question, the answer is almost always DBSCAN.
Updated On: Aug 6, 2026
  • K-Means
  • Mean shift
  • DBSCAN
  • Agglomerating hierarchical clustering
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The Correct Option is C

Solution and Explanation

Concept:
• Clustering is an unsupervised learning task that groups similar data points together.
• Traditional algorithms like K-Means assume that clusters are spherical and of similar size, which is often not true for real-world data.
• Density-based clustering identifies regions of high point density separated by regions of low point density.

Step 1:
Analyze the limitations of K-Means and Hierarchical clustering
K-Means (Option A) uses a distance-based approach to minimize the sum of squared distances to centroids. This forces clusters to be convex/spherical. It is also highly sensitive to outliers (noise), as noise points can significantly pull the centroids away from the true cluster center. Hierarchical clustering (Option D) is also primarily distance-based and lacks a built-in mechanism to ignore noise.

Step 2:
Evaluate DBSCAN (Density-Based Spatial Clustering of Applications with Noise)
DBSCAN defines clusters based on two parameters: \(\epsilon\) (epsilon - radius) and \(MinPts\) (minimum points).
Core Points: Points that have at least \(MinPts\) within their \(\epsilon\)-neighborhood.
Border Points: Points that are within the neighborhood of a core point but don't have enough neighbors themselves.
Noise Points: Points that are neither core nor border points. Because it connects adjacent high-density regions, it can follow any "trail" of data, allowing it to find clusters of arbitrary shapes (like "moons" or "donuts").

Step 3:
Conclusion on Noise Handling
Unlike other algorithms that force every point into a cluster, DBSCAN explicitly labels isolated points as "Noise." This makes it exceptionally robust in datasets where outliers are prevalent.
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