Question:

Which carbon atoms of $\alpha - D$ glucose and $\beta - D$ fructose respectively forms glycosidic linkage in sucrose?

Show Hint

Sucrose involves the anomeric carbons of both sugars, which is why it is a non-reducing sugar.
Updated On: Apr 26, 2026
  • C — 1 and C — 2
  • C-2 and C-1
  • C-2 and C-6
  • C-1 and C-5
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Concept
Sucrose is a non-reducing disaccharide. It is formed by the condensation of one molecule of $\alpha-D$-glucopyranose and one molecule of $\beta-D$-fructofuranose.
Step 2: Linkage Analysis
The glycosidic bond is formed between the anomeric carbon atoms of both units: - $\text{C}_1$ of $\alpha-D$-glucose. - $\text{C}_2$ of $\beta-D$-fructose.
Step 3: Conclusion
The linkage is specifically $\alpha-1,2$-glycosidic linkage.
Final Answer: (A)
Was this answer helpful?
0
0