Question:
Which carbon atom of glucopyranose numbered from \(\mathrm{C}-1\) to \(\mathrm{C}-6\) is anomeric?
Which carbon atom of glucopyranose numbered from \(\mathrm{C}-1\) to \(\mathrm{C}-6\) is anomeric?
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The anomeric carbon is the carbonyl carbon that becomes the new chiral centre when the ring forms.
Updated On: Nov 13, 2026
- \(\mathrm{C}-5\)
- \(\mathrm{C}-6\)
- \(\mathrm{C}-2\)
- \(\mathrm{C}-1\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
In glucose the aldehyde carbon C-1 reacts with the OH on C-5 to form the six-membered pyranose ring.
Step 2: Ring Formation
This creates a new chiral centre at C-1, giving the alpha and beta forms, which are called anomers.
Step 3: Result
So the anomeric carbon is C-1.
Final Answer:
C-1 is the anomeric carbon. \[ \boxed{\text{(D) }\text{C-1}} \]
In glucose the aldehyde carbon C-1 reacts with the OH on C-5 to form the six-membered pyranose ring.
Step 2: Ring Formation
This creates a new chiral centre at C-1, giving the alpha and beta forms, which are called anomers.
Step 3: Result
So the anomeric carbon is C-1.
Final Answer:
C-1 is the anomeric carbon. \[ \boxed{\text{(D) }\text{C-1}} \]
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