Step 1: Understanding the Question:
We need to identify the strongest carboxylic acid derivative from the given options based on the inductive effect.
Step 2: Detailed Explanation:
The strength of a halogen-substituted acid depends directly on the electron-withdrawing power ($-I$ effect) of the attached halogen atom.
A stronger $-I$ effect pulls electron density away from the $O-H$ bond, facilitating the release of the $H^+$ ion and stabilizing the resulting carboxylate conjugate base.
The order of electronegativity for halogens is: $F > Cl > Br > I$.
Because fluorine is the most electronegative element, it exerts the strongest $-I$ effect.
Therefore, fluoroacetic acid ($F-CH_2-COOH$) forms the most stable conjugate base and is the strongest acid among the choices.
Step 3: Final Answer:
The strongest acid is fluoroacetic acid, matching option (B).