Question:

Which among the following is NOT an octahedral complex?

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Platinum(II) complexes commonly show square planar geometry.
Updated On: Feb 11, 2026
  • \([\mathrm{Ir(C_2O_4)_2Cl_2}]^{3-}\)
  • \([\mathrm{CoCl_2(en)_2}]^+\)
  • \([\mathrm{Co(en)_2(NO_3)_2}]^+\)
  • \([\mathrm{Pt(NH_3)_2Cl_2}]\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding octahedral geometry.
An octahedral complex has coordination number 6, meaning six ligand donor atoms are attached to the central metal ion.

Step 2: Checking coordination numbers.
Options (A), (B), and (C) all have six donor atoms around the metal ion, leading to octahedral geometry.

Step 3: Analyzing option (D).
\([\mathrm{Pt(NH_3)_2Cl_2}]\) has coordination number 4 and forms a square planar complex, not octahedral.

Step 4: Conclusion.
Hence, \([\mathrm{Pt(NH_3)_2Cl_2}]\) is NOT an octahedral complex.
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