Step 1: Understand bond dissociation energy trend.
Bond dissociation energy decreases as bond length increases. Step 2: Analyze group 16 hydrides.
Down the group from oxygen to tellurium, atomic size increases and M–H bond length increases. Step 3: Compare given hydrides.
\[
\text{O–H}>\text{S–H}>\text{Se–H}>\text{Te–H}
\]
Thus, H\(_2\)Te has the weakest M–H bond. Step 4: Conclusion.
H\(_2\)Te has the lowest bond dissociation energy.