Step 1: Understanding the Concept
Diborane (\(\text{B}_2\text{H}_6\)) is an electrophilic reducing agent. It attacks electron rich groups, and a carboxylic acid reacts fastest.
Step 2: Reaction
\(\text{RCOOH} \xrightarrow{\text{B}_2\text{H}_6/\text{THF},\ \text{H}_2\text{O}} \text{RCH}_2\text{OH}\)
Step 3: Compare the options
Diborane reduces \(-\text{COOH}\) selectively. It does not reduce \(-\text{NO}_2\) or alkyl halide groups, and esters react much more slowly.
Final Answer:
The carboxylic acid group \(-\text{COOH}\) is reduced by diborane.
\[ \boxed{\text{(B) }-\text{COOH}} \]