Question:

Which among the following compounds is obtained when benzene is treated with CO and HCl in presence of catalyst anhydrous \( \mathrm{AlCl_3} \) and \( \mathrm{Cu_2Cl_2} \) under high pressure?

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Gattermann–Koch reaction is specifically used for introducing the \(-CHO\) group into aromatic rings.
Updated On: Feb 11, 2026
  • Toluene
  • Benzoic acid
  • Benzaldehyde
  • Acetophenone
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The Correct Option is C

Solution and Explanation

Step 1: Identifying the reaction.
The reaction of benzene with carbon monoxide and hydrogen chloride in presence of anhydrous \( \mathrm{AlCl_3} \) and \( \mathrm{Cu_2Cl_2} \) is known as the Gattermann–Koch reaction.

Step 2: Reaction outcome.
In this reaction, a formyl group (\(-CHO\)) is introduced into the benzene ring, resulting in the formation of benzaldehyde.

Step 3: Elimination of incorrect options.
Toluene and acetophenone are alkylated products, while benzoic acid is formed through oxidation, not this reaction.

Step 4: Conclusion.
Therefore, the correct product obtained is benzaldehyde.
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