Question:
Which among the following compounds has lowest boiling point?
Which among the following compounds has lowest boiling point?
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No H on the N or O? No intermolecular H-bonding. Tertiary amines always boil lower than primary/secondary amines of similar mass.
Updated On: May 14, 2026
- $(\text{C}_2\text{H}_5)_2\text{NH}$
- $\text{C}_2\text{H}_5\text{N}(\text{CH}_3)_2$
- $n-\text{C}_4\text{H}_9\text{OH}$
- $\text{C}_2\text{H}_5\text{COOH}$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Boiling points are determined by the strength of intermolecular forces, primarily hydrogen bonding in these functional groups.
Step 2: Meaning
Primary and secondary amines, alcohols, and carboxylic acids can form intermolecular hydrogen bonds.
Step 3: Analysis
- (D) Carboxylic acid and (C) Alcohol have the strongest H-bonds. - (A) is a secondary amine ($\text{R}_2\text{NH}$), which has H-bonding. - (B) is a tertiary amine ($\text{R}_3\text{N}$), which has no hydrogen directly attached to Nitrogen. Therefore, it cannot form intermolecular hydrogen bonds with itself.
Step 4: Conclusion
The lack of intermolecular hydrogen bonding in the tertiary amine leads to the lowest boiling point. Final Answer: (B)
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