Question:
Which among the following compounds has highest boiling point?
Which among the following compounds has highest boiling point?
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Among isomeric amines, boiling point depends on the extent of intermolecular hydrogen bonding and on surface area.
Updated On: Nov 13, 2026
\(n-\mathrm{C}_{4}\mathrm{H}_{9}\mathrm{NH}_{2}\)
\((\mathrm{C}_{2}\mathrm{H}_{5})_{2}\mathrm{NH}\)
\(\mathrm{C}_{2}\mathrm{H}_{5}\text{ }\mathrm{N}(\mathrm{CH}_{3})_{2}\)
\((\mathrm{CH}_{3})_{3}-\mathrm{C}-\mathrm{NH}_{2}\)
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Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Primary amines have two N-H bonds and form the most hydrogen bonds. Tertiary amines have no N-H bond and cannot form hydrogen bonds with each other.
Step 2: Compare the amines
All four compounds are isomers of formula \(\text{C}_4\text{H}_{11}\text{N}\).
n-Butylamine is a primary amine with a long straight chain.
Diethylamine is secondary, the tertiary amine has no H-bonding, and tert-butylamine is primary but highly branched, giving a smaller surface area.
Step 3: Compare the options
n-Butylamine has the highest boiling point of about 78 \(^{\circ}\)C.
Final Answer:
n-Butylamine has the highest boiling point because of strong hydrogen bonding and a straight chain. \[ \boxed{\text{(A) }n-\text{C}_{4}\text{H}_{9}\text{NH}_{2}} \]
Primary amines have two N-H bonds and form the most hydrogen bonds. Tertiary amines have no N-H bond and cannot form hydrogen bonds with each other.
Step 2: Compare the amines
All four compounds are isomers of formula \(\text{C}_4\text{H}_{11}\text{N}\).
n-Butylamine is a primary amine with a long straight chain.
Diethylamine is secondary, the tertiary amine has no H-bonding, and tert-butylamine is primary but highly branched, giving a smaller surface area.
Step 3: Compare the options
n-Butylamine has the highest boiling point of about 78 \(^{\circ}\)C.
Final Answer:
n-Butylamine has the highest boiling point because of strong hydrogen bonding and a straight chain. \[ \boxed{\text{(A) }n-\text{C}_{4}\text{H}_{9}\text{NH}_{2}} \]
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