Step 1: Understanding optical activity.
A compound is optically active if it has a chiral center (a carbon atom with four different substituents). Sec-butyl iodide has a chiral center, making it optically active. Step 2: Analyzing the options. (A) Isobutyl chloride: Incorrect. Isobutyl chloride is not optically active because it does not have a chiral center. (B) tert. butyl bromide: Incorrect. tert-butyl bromide is not optically active because it has no chiral center. (C) sec. butyl iodide: Correct. sec-butyl iodide has a chiral center and is optically active. (D) n butyl bromide: Incorrect. n-butyl bromide is not optically active because it does not have a chiral center. Step 3: Conclusion.
The correct answer is (C) sec. butyl iodide.