Step 1: Understanding resolving power.
The resolving power \( R \) of an optical instrument is inversely proportional to the wavelength \( \lambda \) of the light used. This means that the instrument with a smaller wavelength will have a greater resolving power.
Step 2: Calculating the ratio.
Let \( R_A \) and \( R_B \) be the resolving powers of instruments A and B, respectively. We have:
\[
\frac{R_A}{R_B} = \frac{\lambda_B}{\lambda_A}
\]
Substitute the values for \( \lambda_A \) and \( \lambda_B \):
\[
\frac{R_A}{R_B} = \frac{6000}{4500} = \frac{4}{3}
\]
Step 3: Conclusion.
The ratio of the resolving power of A to B is \( 4 : 3 \), hence the correct answer is (D) 4 : 3.